Find the speed of an object using work and energy

In summary: JIn summary, an object with mass 100 kg moved in outer space at a speed of 3.5 m/s when it was at location < 9,-24,-4>. As it moved from location < 9,-24,-4> m to location < 15,-17,-8> m, a single constant force of <250,400,-170> N acted on the object. Then, while the object moved from location < 15,-17,-8> m to location < 19,-24,-3> m, a different single constant force of <140,250,150> N acted on the object. The speed of the object at the final location is 10.2 m
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shepherd882
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Homework Statement


An object with mass 100 kg moved in outer space. When it was at location < 9,-24,-4 > its speed was 3.5 m/s. A single constant force < 250,400,-170 > N acted on the object while the object moved from location < 9,-24,-4 > m to location < 15,-17,-8 > m. Then a different single constant force < 140,250,150 > N acted on the object while the object moved from location < 15,-17,-8 > m to location < 19,-24,-3 > m. What is the speed of the object at this final location?

Homework Equations


Kf = Ki + W1 + W2
W = F*displacement

The Attempt at a Solution


W1 = <250, 400,-170>*<6,7,-4> = 4980J
W2 = <140,250,150>*<4,7,5> = 3060J

Kf = Ki + W1 + W2
1/2(100)vf^2 = 1/2(100)(vi)^2 + W1 + W2
1/2(100)vf^2 = 1/2(100)(3.5)^2 + 4980 + 3060
50vf^2 = 612.5 + 8040
vf^2 = 173.05
vf = 13.2 m/s

(the answer's supposed to be 10.2 m/s) Thanks in advance!
 
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  • #2
shepherd882 said:

Homework Statement


An object with mass 100 kg moved in outer space. When it was at location < 9,-24,-4 > its speed was 3.5 m/s. A single constant force < 250,400,-170 > N acted on the object while the object moved from location < 9,-24,-4 > m to location < 15,-17,-8 > m. Then a different single constant force < 140,250,150 > N acted on the object while the object moved from location < 15,-17,-8 > m to location < 19,-24,-3 > m. What is the speed of the object at this final location?

Homework Equations


Kf = Ki + W1 + W2
W = F*displacement

The Attempt at a Solution


W1 = <250, 400,-170>*<6,7,-4> = 4980J
W2 = <140,250,150>*<4,7,5> = 3060J

Kf = Ki + W1 + W2
1/2(100)vf^2 = 1/2(100)(vi)^2 + W1 + W2
1/2(100)vf^2 = 1/2(100)(3.5)^2 + 4980 + 3060
50vf^2 = 612.5 + 8040
vf^2 = 173.05
vf = 13.2 m/s

(the answer's supposed to be 10.2 m/s) Thanks in advance!
Check the sign of the red number in W2 = <140,250,150>*<4,7,5>
 
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1. How do you calculate the speed of an object using work and energy?

The speed of an object can be calculated using the formula: speed = √(2*work/ mass), where work is the force applied to move the object and mass is the mass of the object.

2. Can you explain the concept of work and energy in relation to calculating speed?

Work is the amount of force applied to move an object a certain distance, while energy is the ability of an object to do work. In order to calculate the speed of an object, we use the principle of conservation of energy, which states that the total energy in a system remains constant. By applying a known force to an object and measuring the work done, we can determine the object's energy and therefore its speed.

3. What are the units of measurement for work and energy?

The standard unit of measurement for both work and energy is joules (J). However, work can also be measured in newton-meters (N*m) since it is the product of force and distance, while energy can also be measured in kilowatt-hours (kWh) for larger amounts of energy.

4. Is it possible for an object's speed to be calculated without using work and energy?

Yes, an object's speed can also be calculated using other formulas, such as speed = distance/ time or speed = acceleration * time. However, these formulas are based on different principles and may not be as accurate as using work and energy.

5. What are the limitations of using work and energy to calculate an object's speed?

One limitation is that this method assumes that there are no other external forces acting on the object, which may not always be the case. Additionally, this method may not be suitable for objects that have varying mass or for objects that are not moving in a straight line. It is important to consider the specific conditions and limitations of this method when applying it to a problem.

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