# Calculating the thrust required to turn a submarine deep in the water

In summary, the conversation discusses the design of an AUV with a front bow thruster and the power needed to turn the vehicle at a steady angular velocity. The individual requesting help is asked to provide more information about the AUV's weight, size, power consumption, and desired turning time. It is suggested to calculate the drag while turning by comparing it to the power needed to hold the vessel stationary against currents. The use of rotating pods for primary propulsion is also mentioned as a possible solution.
Dear All,

I am designing a AUV and trying putting a bow thruster in the front. I am kinda confused that how much power do I need to turn my AUV by a steady angular velocity. Could anyone pls help me with this.

Regards

Working blind here.
Power could be any value. I am guessing it should be about 0.1 HP.

Firstly, briefly describe your AUV - weight, size, power consumption, duration of underwater expedition, desired time to make a turn, etc. That might cog someone with experience with a similar problem or knowledge of underwater vehicles to offer aid.

You must at least have some idea of what your desired goal is.
And how much knowledge you have on this subject would not hurt either.

1 person
I am looking for the formulas or the procedure to calculate the drag while turning for any typical AUV of any size.

I would guess that drag is small compared to the forces caused by currents impinging at angles such as 45 degrees.

Here is a way to guess. Calculate, or fiind by experiment, how much primary propulsion power is needed to hold the vessel stationary against X knots of current bow-on. The power needed by the thruster and rudder to hold constant angle against X knots at 45 degrees is comparable within a factor of two.

Your biggest job is to decide how much X to design for. Unless you are in a swimming pool, X is seldom zero.

Good luck

Ah, Cant do experiments. Anything mathematically

Can you make the primary propulsion in pods that rotate 360 degrees? Modern ships do that. One pod fore, one aft and you have it. No separate thruster needed.

## 1. What is the formula for calculating the thrust required to turn a submarine deep in the water?

The formula for calculating the thrust required to turn a submarine deep in the water is: T = m * v * r where T is the thrust in Newtons, m is the mass of the submarine in kilograms, v is the velocity of the water in meters per second, and r is the radius of the turn in meters.

## 2. How does the depth of the water affect the thrust required to turn a submarine?

The depth of the water does not directly affect the thrust required to turn a submarine. However, the density of the water does play a role in determining the velocity of the water, which is a factor in the thrust calculation.

## 3. Can you calculate the thrust required to turn a submarine using only its weight?

No, the weight of the submarine alone is not enough information to calculate the thrust required to turn it. The velocity of the water and the radius of the turn are also necessary to determine the required thrust.

## 4. Is there a maximum speed at which a submarine can turn while maintaining a certain depth?

Yes, there is a maximum speed at which a submarine can turn while maintaining a certain depth. This is due to the physical limitations of the submarine's structure and the amount of thrust it can generate.

## 5. How can the calculated thrust required to turn a submarine be used in practical applications?

The calculated thrust required to turn a submarine can be used in various ways, such as designing more efficient propulsion systems and determining the maximum turning speed for safe operation. It can also be used to analyze the performance of different submarine models and make improvements for future designs.

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