Calculating the Time Difference in Special Relativity: Alphonse's Joy Ride

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Homework Help Overview

The problem involves calculating the time experienced by Alphonse, who travels at a significant fraction of the speed of light, as perceived by his twin brother Carl. The context is rooted in the principles of special relativity, specifically time dilation.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the conversion of time units and the implications of using different units in the calculations. There is an exploration of the formula for time dilation and the significance of the ratio of velocities. Some participants question the accuracy of the calculations and the interpretation of significant figures.

Discussion Status

The discussion has revealed various interpretations of the problem, particularly regarding unit conversions and the application of the time dilation formula. Some participants have offered guidance on potential errors in calculations, while others have noted discrepancies in the expected answer format. There is an acknowledgment of the need for clarification from the original poster's physics teacher.

Contextual Notes

Participants note that the online assignment has specific requirements for the unit of time, which has led to confusion. There is mention of the original poster's misunderstanding regarding the acceptance of years as a unit in the assignment.

Curious&TheNon
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Homework Statement


Alphonse decides to go for a joy ride in his Astro-Scooter. He maintains a speed of 0.604 c and is gone for 6.53 years according to his ship's clock. His twin brother Carl says he is full of beans. According to Carl, how long has Alphonse been gone?
To=?
T=6.53 years?
v=0.604c
c=3*10^8

Homework Equations


T= To/ (Sqrt of (1- v^2 / c^2)

The Attempt at a Solution


So first i noticed i had to convert the years into seconds because the other variables were in seconds (m/s). So i multiplied 6.53 by 365*24*60*60 to make it into seconds (205930080sec). Which then i plugged it into the formula as T. As for the velocity and the speed of light, the "c" cancels out because the velocity it measured by a fraction of the speed of light so then it would only look like this Sqrt of (1-0.604^2 ) for the denominator. I then multiplied the "T" by the denominator of "To" to get To by itself. The answer came out to be 164123044 seconds however i still got it wrong. Then i tried the other way where this time "T" was To , which came out to be 2583866150.5 seconds but still wrong, I am not sure which variable is right and what i mis calculated. Help is appreciated thank you :)
 
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Look, ##\frac{v^2} { c^2}## is just a ratio. So you need not change the unit in this problem.
 
arpon said:
Look, ##\frac{v^2} { c^2}## is just a ratio. So you need not change the unit in this problem.
My online assignment doesn't accept years as a unit though, only hours, minutes and seconds :/
 
Curious&TheNon said:
2583866150.5
Is that exactly what you entered? You seem to have an extra digit in there.
 
haruspex said:
Is that exactly what you entered? You seem to have an extra digit in there.
No not exactly i had to put it in sig figs which was three, so it came out to be 2.58E9. Ignore the extra digit my bad X)
 
Curious&TheNon said:
No not exactly i had to put it in sig figs which was three, so it came out to be 2.58E9. Ignore the extra digit my bad X)
I wouldn't have affect the answer anyways
 
Curious&TheNon said:
I wouldn't have affect the answer anyways
It would, since what you first posted was 10 times too much.
 
Oh, thought you were talking about the decimal place, my bad. Anyways got 258386615.5 , just tried entering it again, however still wrong :/ Thanks for the header though! :)
 
Curious&TheNon said:
Oh, thought you were talking about the decimal place, my bad. Anyways got 258386615.5 , just tried entering it again, however still wrong :/ Thanks for the header though! :) that was probably a typo x)
 
  • #10
Curious&TheNon said:
Oh, thought you were talking about the decimal place, my bad. Anyways got 258386615.5 , just tried entering it again, however still wrong :/ Thanks for the header though! :)
Then I'm stumped. 2.58E9 seconds looks right to me. Maybe... if you allow a year as 365.25 days, it just tips over to 2.59E9.
 
  • #11
haruspex said:
Then I'm stumped. 2.58E9 seconds looks right to me. Maybe... if you allow a year as 365.25 days, it just tips over to 2.59E9.
Yeah still wrong dam i guess ill just ask my physics teacher about it this coming tuesday ill keep you posted hahaha thanks anyways though! :)
 
  • #12
Turns out the online assignment didnt mention they took years, so my physics teacher forgot to mention he customized the answer to accept it in years as well. Problem solved thanks!
 
  • #13
Curious&TheNon said:
Turns out the online assignment didnt mention they took years, so my physics teacher forgot to mention he customized the answer to accept it in years as well. Problem solved thanks!
Thanks for letting me know.
 

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