Calculating the time of an falling object provding with only speed and weight

• nikkkk
In summary, a stone is falling from the top of a building with a velocity of 32m/s. The air resistance is negligible and the weight of the stone is 24N. To calculate the time it takes for the stone to reach the ground, the forum rules state that the user must show their work and provide their thoughts before receiving help.
nikkkk
Question: A stone is falling from the top of a buliding with 32m/s.
Air resistance is so small that it can be neglected.
the weight of the stone is 24N.
Calculate the time in second which the stone takes to reache the ground.

nikkkk said:
Question: A stone is falling from the top of a buliding with 32m/s.
Air resistance is so small that it can be neglected.
the weight of the stone is 24N.
Calculate the time in second which the stone takes to reache the ground.

Read the forum rules for posts in the homework section:

You are required to show your work and give your thoughts before receiving help.

CS

To calculate the time it takes for the stone to reach the ground, we can use the equation t = √(2h/g), where t is the time, h is the height of the building, and g is the acceleration due to gravity. In this case, the height of the building can be assumed to be zero since the stone is falling from the top. Therefore, the equation can be simplified to t = √(2/g).

Using the given information, we can determine the value of g by dividing the weight of the stone (24N) by its mass (m) which can be calculated using the formula w = mg. Therefore, m = w/g = 24N/9.8m/s^2 = 2.45 kg.

Substituting this value of g (9.8m/s^2) in the equation t = √(2/g), we get t = √(2/9.8) = 0.45 seconds.

Therefore, the stone takes approximately 0.45 seconds to reach the ground. However, it is important to note that this calculation assumes that there is no air resistance acting on the stone. In reality, air resistance will have a small impact on the time it takes for the stone to fall, but it can be neglected in this scenario.

1. How is the time of a falling object calculated?

The time of a falling object can be calculated using the formula t = √(2h/g), where t is the time in seconds, h is the height of the object in meters, and g is the acceleration due to gravity (9.8 m/s²).

2. Can the time of a falling object be calculated if only the speed and weight are known?

Yes, the time of a falling object can still be calculated if only the speed and weight are known. The formula t = v/g can be used, where t is the time in seconds, v is the initial velocity of the object, and g is the acceleration due to gravity.

3. What is the unit of measurement for time when calculating the time of a falling object?

The unit of measurement for time when calculating the time of a falling object is seconds (s).

4. Does the weight of the object affect the time it takes to fall?

Yes, the weight of an object does affect the time it takes to fall. Heavier objects will fall faster than lighter objects due to the force of gravity acting on them.

5. Can the time of a falling object be calculated if the object is dropped from a height above the ground?

Yes, the time of a falling object can still be calculated if the object is dropped from a height above the ground. The formula t = √(2h/g) can be used, where h is the height of the object above the ground. However, this only applies if the object is dropped in a vacuum, where air resistance is not a factor.

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