Calculating the velocity given the position of the particle

Click For Summary
SUMMARY

The discussion focuses on calculating the velocity and acceleration of a particle moving along the curve defined by r = e^(θ) and z = r in cylindrical coordinates, with a constant speed, v. The velocity is expressed as v = dr/dt + r dθ/dt, and the relationship between velocity and acceleration is established, demonstrating their perpendicularity. Additionally, the expression for θ(t) is derived based on the constant speed condition.

PREREQUISITES
  • Cylindrical coordinates and their applications
  • Understanding of velocity and acceleration in physics
  • Basic calculus, particularly derivatives
  • Knowledge of constant speed motion
NEXT STEPS
  • Study the derivation of velocity in cylindrical coordinates
  • Learn about the relationship between velocity and acceleration in vector calculus
  • Explore the concept of parametric equations in motion
  • Investigate the implications of constant speed on particle motion
USEFUL FOR

Students in physics or engineering, particularly those studying kinematics and dynamics, as well as educators looking to enhance their understanding of motion in cylindrical coordinates.

TheLil'Turkey
Messages
66
Reaction score
0

Homework Statement


A particle moves with constant velocity along the curve r = e^(θ) and z = r (cylindrical coordinates). The speed, v, is constant.

a) Calculate the velocity and acceleration of the particle in terms of θ and v.

b) Show that the velocity and acceleration are perpendicular.

c) Find the expression for θ(t).

Homework Equations


v[/B] = dr/dt (radial direction) + r dθ/dt (tangential direction)

v^2 = (dr/dt)^2 + r^2 (dθ/dt)^2 = constant

dr/dt = dr/dθ dθ/dt

The Attempt at a Solution



Mecaacutenica%20Teoacuterica_zpsvo48slj3.png
 
Physics news on Phys.org
TheLil'Turkey said:
v = dr/dt (radial direction) + r dθ/dt (tangential direction)
That's for 2 dimensions. This is moving in three.

Posting your algebra as an image makes it hard to refer to specific equations in comments.

Expressing dr/dt in terms of dθ/dt, then expressing that in terms of dr/dt is going round in circles. Get all the velocity components expressed in terms of the time derivative of one of the coordinates - r, θ, or z, whichever is easiest - as you eventually did.
 

Similar threads

Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 42 ·
2
Replies
42
Views
6K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K