Calculating the voltage across capacitors and resistors with switches

  • Thread starter Thread starter radioglava
  • Start date Start date
AI Thread Summary
In the discussion, participants clarify that with switch K1 open, there is no voltage across resistor R1 or capacitor C1, leading to confusion about the current's path. The consensus is that since no current flows through C1, its voltage remains at the emf level, while capacitor C2 retains a voltage of zero. The participants seek to understand the voltage dynamics before and after closing switch K2. They emphasize the importance of analyzing the equivalent circuit to determine voltage changes across the capacitors. The conversation highlights the complexities of circuit behavior when switches are manipulated.
radioglava
Messages
1
Reaction score
1
Homework Statement
Figure 89 is schematically represented by a circuit whose elements are: E = 60 V, R1= 3R2, C1 = 2C2. The internal resistance of the source is negligible. Determine the voltage on the capacitors in the following cases: a) switches K1, and K2 are closed, b) switch K2 open, a K1, closed, c) switch K2 closed, a K1 open.
Relevant Equations
I=U/R
U=C×Q
We had this for homework, my friends and I were able to solve the problems labeled with a) and b), but we got stuck at c).

From what we understood there is no voltage in resistor R1 because switch K1 is open. Resistor R1 is parallel to capacitor C1 so there is no voltage in capacitor C1, either. Our question is where does the current go if it can't go through C1? We know that the current must always return to the cell.

However, our textbook says that the voltage across capacitor 2 (C2) is equal to zero, and that the voltage across the first capacitor (C1) is equal to the emf.
 

Attachments

  • IMG_20250516_130127_315.webp
    IMG_20250516_130127_315.webp
    13.4 KB · Views: 16
Physics news on Phys.org
Great post, yeah part © is little tricky. I think C1 its voltage from earlier since no current flows with k1 open. C2 does not charge at all i guess, so its voltage stays at zero. That’s how i understand it at least.
 
Look at the redrawn equivalent circuit below when ##K_1## is and stays open. Then answer the following two questions.
  1. What is the voltage across each capacitor before ##K_2## is closed?
  2. How does the voltage across each capacitor change after ##K_2## is closed and why?

RC Circuit.webp
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...

Similar threads

Back
Top