The discussion focuses on calculating the wavelength ratio of Kα X-ray lines for copper (Cu) and molybdenum (Mo), specifically λCu/λMo. The correct ratio is identified as approximately 0.48, derived using Moseley's formula, which relates the wavelengths of X-ray emissions to atomic numbers. Participants emphasize the importance of understanding the De Broglie relation (λ = h/p) for calculating momentum, while also suggesting online resources for quick answers.
PREREQUISITESStudents in physics, researchers in material science, and anyone interested in X-ray spectroscopy and atomic physics will benefit from this discussion.
There is some other formula. I google "k-alpha x-ray energy"and wikipedia tells me the answer straight away. You can do that too !Raghav Gupta said:Homework Statement
If λCu is the wavelength of Kα X-ray line of copper (atomic number 29) and λMo is the wavelength of the KαX-Ray line of molybdenum (atomic number 42), then the ratio λCu/λMo is close to
1.99
2.14
0.50
0.48
Homework Equations
De broglie relation λ = h/p
The Attempt at a Solution
How to calculate momentum?
Or is there some other formula?
Oh, so that is Moseley's formula. Never seen that.BvU said:There is some other formula. I google "k-alpha x-ray energy"and wikipedia tells me the answer straight away. You can do that too !