Unique λ at which X-ray and electron have same energy

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catkin
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Homework Statement


Derive an equation to show that there is a unique wavelength at which X-ray photons and electrons have the same energy. Calculate this wavelength and energy.

Homework Equations


Here's what I thought was relevant. There may be others!

For photons: E = hf = h c / λ

For electrons:
λ = h / p (de Broglie)
K.E. = ½ mv^2
p = mv

The Attempt at a Solution


p = √(2mE)
Substituting in de Broglie
λ = h / √(2mE)
E = h^2 / 2mλ^2

Equating energies
(h c / λ)X-ray = (h^2 / 2mλ^2)electron
Gathering the constants (c, h, 2 and m -- the rest mass of an electron)
(λ)X-ray = (h / 2cm) * (λ^2)electron

... which does not have a unique solution :-(
 
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Thanks Borek :)

(nice hair!)

That's what the question asks the answerer to show so I hope it's true! I don't think I've shown that it is so.

Writing y for (λ)X-ray, x for (λ)electron and lumping the constants together as k my attempt shows, when the X-ray and electron energies are the same,
y = k x^2

Mmm ... the more I read the question the more ambiguous it becomes. Perhaps it would help if you could translate the question into unambiguous language.

Best

Charles
 
Why do you still use two variables for wavelength, when you should use one?
 
Thanks again, Borek.

I need to show that λ = fe(E) and λ = fp(E) intersect before that is legitimate (subscript e for electron, p for photon).

With that requirement now clear ...

For photons:
λ = hc / E
= (hc) * (1 / E)

For electrons:
λ = sqrt(h^2 / 2mE)
= sqrt(h^2 / 2m) * sqrt(1 / E)

Regardless of the constant values, these functions intersect once.

At the intersect the previous equation becomes (thanks!)
λ = (h / 2cm) * (λ^2)
= 2cm / h

and the rest is trivial.