Calculating the Wavelength Ratio of Kα X-Ray Lines for Copper and Molybdenum

  • #1
Raghav Gupta
1,011
76

Homework Statement



If λCu is the wavelength of Kα X-ray line of copper (atomic number 29) and λMo is the wavelength of the KαX-Ray line of molybdenum (atomic number 42), then the ratio λCuMo is close to
1.99
2.14
0.50
0.48

Homework Equations


De broglie relation λ = h/p

The Attempt at a Solution


How to calculate momentum?
Or is there some other formula?
 
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  • #2
Raghav Gupta said:

Homework Statement



If λCu is the wavelength of Kα X-ray line of copper (atomic number 29) and λMo is the wavelength of the KαX-Ray line of molybdenum (atomic number 42), then the ratio λCuMo is close to
1.99
2.14
0.50
0.48

Homework Equations


De broglie relation λ = h/p

The Attempt at a Solution


How to calculate momentum?
Or is there some other formula?
There is some other formula. I google "k-alpha x-ray energy"and wikipedia tells me the answer straight away. You can do that too !
 
  • #3
BvU said:
There is some other formula. I google "k-alpha x-ray energy"and wikipedia tells me the answer straight away. You can do that too !
Oh, so that is Moseley's formula. Never seen that.
It was formula oriented , okay.
 
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