Calculating the Z Component of a Force: Solving for the Unknown Vector Component

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Homework Help Overview

The discussion revolves around calculating the components of a force vector, specifically focusing on the z component of a 200 kN force. Participants are exploring the relationships between the force components in the x, y, and z directions, referencing vector mechanics principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss methods for calculating the z component, with some suggesting the use of projections onto the x-z plane. Questions arise about the angles used in calculations and the reasoning behind specific formulas for the components.

Discussion Status

The discussion is active, with various participants sharing their calculations and approaches. Some have expressed confusion about the angles and methods, while others are attempting to clarify these points. There is a mix of correct and uncertain reasoning being explored.

Contextual Notes

Participants mention reliance on external resources such as textbooks and online materials, indicating potential gaps in understanding or missing information. There is also a sense of urgency expressed by the original poster regarding the need for assistance.

Brophi
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What are the components of the 200kN force along, the x, y and z directions?
http://img7.imageshack.us/img7/1358/72180912.jpg

So, I can find the x and y components, but I don't know how to find the z component, I have been researching on the internet, my textbook (Vector Mechanics for Engineers: Statics) and in my lecture notes, but I just can't find how to find the z component.

Fx = 200cos 41.4 = 150 N
Fy = 200sin 30 = 100 N
Fz = ?

Please HELP!

P.S. Sorry if the post isn't in the right format, but I need the answer soon and I only just registered..
 
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How did you get Fx=200*cos(41.4)? That's the right answer, but it's not how I would have done the question.

The projection of the force on the x-z plane is F*cos(30), correct? Now you can split this force, F*cos(30), into its x and z components just like you do with any vector in 2 dimensions.
 
Hi Brophi, welcome to PF.
F*cos(30) is the projection of F on the xz plane.
From that you can find z component.
Can you show your calculation for Fx ? from where did you get 41.4 degree angle?
 
This stuff is all very new and confusing to me but I think I got the the right answer for Fz = 100cos30 = 86.6 and I'm really not sure how I got to this or 41.4 for Fx... Could someone explain it maybe? sorry for the inconvenience, its just kinda frustrating that I can't figure this out (been trying for a ffew hours straight)...
 
I found it! This forum rules...

found the answer at https://www.physicsforums.com/showpost.php?p=1439702&postcount=2

Fx = 200 sin 60 cos 30
Fy = 200 sin 30
Fz = 200 sin 60 sin 30

Thanks for the help!
 
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