Calculating theoretical yield of resulting alum from water dissolving help asap

Click For Summary

Discussion Overview

The discussion revolves around calculating the theoretical yield of alum produced from the dissolution of ammonium sulfate and aluminum sulfate in water. Participants are addressing the balancing of the chemical equation involved, particularly focusing on the presence of hydrates and the concept of limiting reactants.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a mass of (NH4)2SO4 and Al2(SO4)3*18H2O, seeking help to calculate the theoretical yield of alum.
  • Another participant suggests balancing the equation for the reaction between Al2(SO4)3*18H2O and (NH4)2SO4 to yield NH4Al(SO4)2·12H2O.
  • A later reply notes that water needs to be included on the left-hand side of the equation.
  • One participant expresses uncertainty about balancing equations that involve hydrates and the limiting reactant aspect.
  • Another participant advises writing the hydrate as Al2(SO4)3(H2O)18 to clarify the equation.

Areas of Agreement / Disagreement

The discussion shows some agreement on the need to balance the equation and the inclusion of water, but there is uncertainty regarding the correct approach to balancing hydrates and identifying the limiting reactant.

Contextual Notes

Participants have not fully resolved the balancing of the equation, particularly in relation to the hydrates and the limiting reactant concept. There are also missing assumptions regarding the stoichiometry of the reaction.

Who May Find This Useful

Students or individuals studying chemistry, particularly those interested in stoichiometry, chemical reactions involving hydrates, and theoretical yield calculations.

curlyfries4
Messages
2
Reaction score
0
calculating theoretical yield of resulting alum from water dissolving...help asap!

a mass of 13.02g (NH4)2SO4 is dissolved in water. After the solution is heated, 27.22g of Al2(SO4)3*18H2O is added. calculate the theoretical yield of the resulting alum (formula is NH4+(superscript)Al3+(superscript)(SO4)2*12H2O) Hint:this is a limiting reactant problem.

so far I've got 2Al+(NH4)2SO4+H2O yields Al2(SO4)3*18H2O + the formula of alum but I am rly not sure if this is right...please hellppp meeee asap!thanks.
 
Physics news on Phys.org


Balance this first...

Al2(SO4)3*18H2O + (NH4)2SO4 -----> NH4Al(SO4)2·12H2O
 


Note: you will need water on the LHS.
 


but i don't know how to balance with hydrates that well...the limiting reactant side?
 


Write hydrate as Al2(SO4)3(H2O)18. LH stands for left hand.
 

Similar threads

Calculating Yield and Concentrations in a Precipitation Reaction
  • · Replies 4 ·
Replies
4
Views
3K
Chemistry Calculating the number of water molecules in trans. metal complex
  • · Replies 5 ·
Replies
5
Views
3K
I Really Need Help Chemistry: Synthesis of a Coordination Compound
  • · Replies 2 ·
Replies
2
Views
27K
Lab Calculations: How to Find Theoretical Yield
  • · Replies 1 ·
Replies
1
Views
4K
Calculating Theoretical Yield for Copper Reactions: Help with Homework
  • · Replies 16 ·
Replies
16
Views
23K
Theoretical Yield, Molar Mass, and Percent Yield
  • · Replies 1 ·
Replies
1
Views
28K
What Is the Theoretical Yield of Geometric Isomers in This Lab Experiment?
  • · Replies 2 ·
Replies
2
Views
13K
Equilibrium of NH4F, (NH4)2S, and MgO in Water: Reactants or Products?
  • · Replies 33 ·
2
Replies
33
Views
6K
Reaction involving copper (II) sulfate pentahydrate
  • · Replies 3 ·
Replies
3
Views
51K
Calculate AgCl, NaNO3 from 1.3g NaCl + 3.5g AgNO3
  • · Replies 2 ·
Replies
2
Views
13K