calculating theoretical yield of resulting alum from water dissolving....help asap! a mass of 13.02g (NH4)2SO4 is dissolved in water. After the solution is heated, 27.22g of Al2(SO4)3*18H2O is added. calculate the theoretical yield of the resulting alum (formula is NH4+(superscript)Al3+(superscript)(SO4)2*12H2O) Hint:this is a limiting reactant problem. so far ive got 2Al+(NH4)2SO4+H2O yields Al2(SO4)3*18H2O + the formula of alum but im rly not sure if this is right...please hellppp meeee asap!thanks.