Calculating Time and Angle of Impact in Free Fall Physics Problem

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SUMMARY

The discussion focuses on calculating the time of free fall and the angle of impact for an object dropped from a height of 100 meters under the influence of gravity. The relevant equation used is Δy = Voy * t + (1/2)ay * t², where Voy is the initial velocity (5 m/s downward), ay is the acceleration due to gravity (-9.81 m/s²), and Δy is the change in height (-100 m). The correct calculation yields a time of approximately 4.54 seconds for the object to reach the ground, confirming that the negative root is not applicable in this context.

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Homework Statement



http://i1120.photobucket.com/albums/l498/LaLadude/2.jpg

How long does it take to reach the ground? And what is the angle of impact with the ground?

Homework Equations





The Attempt at a Solution


Δy = Voy * t + (1/2)ay * t2
t = (-5 m/s) ± √(5 m/s)2 - 4(1/2)(-9.81 m/s2)(-100m) / 2(1/2)(-9.81 m/s2)

t = -5 m/s ± (4.54)

Is it suppose to be 4.54 or -4.54? And am I suppose to add or subtract the two variables to find t??
 
Last edited:
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Post the entire question.
 
sandy.bridge said:
Post the entire question.

I added a picture link if it'll help.
 

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