Calculating Time Dilation for a Spacecraft Traveling to Proxima Centauri

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Homework Help Overview

The discussion revolves around calculating the time dilation experienced by a spacecraft traveling to Proxima Centauri, which is 4.3 light-years away. The original poster seeks to determine the constant velocity required for the spacecraft to reach the star in 3.7 years as measured by those on board, and how long the journey would take according to observers on Earth.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of time dilation equations and express confusion regarding the relationship between the variables involved, particularly Δt and velocity (v). There are attempts to manipulate the equations to find v, with some questioning the validity of their approaches and the need for additional information.

Discussion Status

Some participants have provided corrections to the equations being used, and there is an ongoing exploration of how to express the Lorentz factor (γ) in terms of velocity. While one participant claims to have found values for v and Δt, the discussion remains open with others still seeking clarity on the relationships between the variables.

Contextual Notes

Participants are working under the constraints of the problem statement and the need to derive relationships between time measurements from different frames of reference without complete information on all variables.

grouper
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Homework Statement



The nearest star to Earth is Proxima Centauri, 4.3 light-years away. At what constant velocity must a spacecraft travel from Earth if it is to reach the star in 3.7 years, as measured by travelers on the spacecraft ? How long does the trip take according to Earth observers?

Homework Equations



Earth observer: Δt=x/(c*√(1-v2/c2))=Δto/√(1-v2/c2) where Δto=time observed by person on spacecraft

Δto=3.7 yr=1.164e8 s

x=4.3 ly=4.068e16 m

c=3.0e8 m/s

The Attempt at a Solution



I tried using the two versions of the equation above with the known quantities plugged in such that (1.164e8/√(1-v2/c2)=4.068e16/(c*√(v2/c2)), but this is a false statement, so there must be something wrong with my equations or the way I am using them because that method does not yield an answer. Any help is appreciated, thanks.
 
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grouper said:
Earth observer: Δt=x/(c*√(1-v2/c2))=Δto/√(1-v2/c2) where Δto=time observed by person on spacecraft
I don't quite understand the first part of that equation. Try:
v = Δx/Δt = Δx/(γΔt0)
 
Thanks for the equation corrections! How do I figure out v without knowing Δt though? (or vice versa?)
 
grouper said:
Thanks for the equation corrections! How do I figure out v without knowing Δt though? (or vice versa?)
You know Δt0. Express γ as a function of v. Then you can solve that equation for v, the only unknown.
 
Ok, working that out I got v=0.759c and Δt according to the Earth observers is 5.68 years, both of which are correct. Thanks for the help.
 

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