I've gotten this for homework from my Electrotechnics class 1. The problem statement, all variables and given/known data You are given two voltages: u1=50 sin(314t + ∏/3) and u2=100 sin(314t - ∏/6). You need to calculate the phase difference (pretty easy, already did that it's 90 degrees) and time when the two voltages have the same value. The solution in the book says 3,16ms. 2. Relevant equations General formula for calculating the voltage is u = Um sin(ωt +- θ). 3. The attempt at a solution So, because it says that I need to find the time both voltages are the same value, u1 must be equal to u2. So, u1=u2 50 sin(314t + ∏/3)=100 sin(314t - ∏/6). Now the problem is how do I get the 't' out of the sine and aren't they going to cancel each other out because they're same? Please ask me anything else you need to solve this problem. THank you.