Alternating Current (multiple CHoice)

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SUMMARY

The discussion centers on solving the problem of determining the time taken by an alternating voltage, defined by the equation v = 30sin(314t), to reach 30V for the first time. The correct answer is identified as 0.015 seconds, derived from the equation 30 = 30sin(314t - π), which indicates the need to account for phase shifts in the sine function. The initial calculation of 0.005 seconds was incorrect due to neglecting the phase adjustment. The conclusion emphasizes the importance of understanding phase shifts in sinusoidal functions.

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Homework Statement


An alternating voltage is given by [tex]v = 30\sin(314t)[/tex].The time taken by the voltage to reach 30V for the first time is:
A. 0.02s
B. 0.03s
C. 0.1s
D. 0.015s

Homework Equations


google for equation for instantaneaous current and voltage

The Attempt at a Solution


30 = 30sin(314t)
1 = sin(314t)
pi/2 = 314t
t = 0.005s
not in the choices

EDIT
30 = 30sin(314t - pi)
pi/2 = (314t - pi)
t = 0.015 from the choices

why do i need to subtract 180 degrees inside the sine eqn instead of adding
( Formula for n repeating cycles is v(t + nT) )
 
Last edited:
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It would appear that the question is incorrect. Starting from time t = 0, the first positive peak occurs at approximately 5ms (milliseconds), which is what you first calculated.

By the way, is that the complete statement of the question in its original form?
 

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