Calculating Time Interval and Speed of Inertial Clock

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SUMMARY

The discussion focuses on calculating the time interval and speed of an inertial clock between two events with a spatial separation of 12 nanoseconds (ns) and a time separation of 24 ns. The calculated timer interval for the clock is 20.78 ns, derived from the equation ΔS = √(Δt² - Δd²). The initial speed calculation yielded 0.58C, which translates to 1.74 m/s; however, it was noted that this calculation mixed reference frame values, necessitating a consistent reference frame for accurate velocity determination.

PREREQUISITES
  • Understanding of special relativity concepts, particularly time dilation and spacetime intervals.
  • Familiarity with the equation ΔS² = Δt² - Δd² for calculating spacetime intervals.
  • Basic knowledge of reference frames in physics.
  • Ability to perform calculations involving nanoseconds and the speed of light (C).
NEXT STEPS
  • Study the implications of spacetime intervals in special relativity.
  • Learn about proper time and its significance in inertial frames.
  • Explore the concept of velocity transformations between different reference frames.
  • Review examples of calculating time dilation and length contraction in special relativity.
USEFUL FOR

Students and educators in physics, particularly those studying special relativity, as well as anyone interested in the mathematical foundations of time and space measurements in inertial frames.

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Homework Statement


In the Home Frame, two events are observed to occur with a spatial separation of 12ns and a time coordination separation of 24ns.

A)An inertial clock travels between these events in such a manner as to be present at both events. What timer interval does this clock read between the events?

B)what is the speed of this clock, as measured in the Home Frame


Homework Equations



ΔS^2 = Δt^2 -Δd^2

The Attempt at a Solution



A) It sounds like the clock is a space-time clock so i assume i am solving for ΔS
ΔS = square root of (24^2 - 12^2) = 20.78 ns

B) For B I did speed = distance/time so i did 12ns/20.78ns to get .58 which means its speed is .58C. Multiply this by 3x10^8 m/s and i get 1.74 m/s
 
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Part A is good. Part B, I'm not really sure what velocity you solved for. It's a velocity that doesn't make sense. You did v=d/t', these are mixed reference frame values. You need to have your reference frames match up with their own values to get the right velocity. As such, there's a couple different formulations for the velocity. One is easy, the other will give you a sanity check and some practice.
 

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