Calculating Time to Apex for Vertically Launched Objects

[get_rekd]

how do you figure out how long it take's an object launched vertically upwards to reach its apex?
V=29.4 m/s

 

[aq1q]

v(final)= Vo + a(t) (a= -9.8)

 

[get_rekd]

so
-29.4 m/s = 29.4 m/s + -9.8t?

-58.8 m/s = -9.8t
----------- ------
-9.8 -9.8

6s = t to reach apex

 

[aq1q]

Vo is given

 

[aq1q]

no when it reaches its apex (highest point), the ball has a speed of zero

 

[get_rekd]

yeah so it is v(final)=29.4 m/s + a(t)
but doesn't an object come back down at the same velocity that it went up?
that is why I thought:
-29.4 m/s = 29.4 m/s + a(t)

 

[aq1q]

right, that's true. but that's not what the question asks. It asks when it reaches its highest point, at the highest point the velocity is 0

 

[get_rekd]

okay so then I should set final velocity to = 0 m/s?

0 m/s = 29.4 m/s + -9.8t
-29.4 m/s = -9.8 t
---------- -------
-9.8 -9.8

t = 3 s ?

 

[get_rekd]

anybody?

 

[aq1q]

yo, that's right

 

[get_rekd]

thanks