Calculating Torque: Window Washer Question

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To calculate the tension in the rope supporting a scaffold with a window washer, the sum of torques must equal zero. The scaffold weighs 185 N and is 3.47 m long, while the window washer weighs 747 N and stands 1 m from one end. The initial torque equation setup was incorrect, as it suggested all torques acted in the same direction, which is not the case. A proper analysis requires identifying the axis of rotation and considering both clockwise and counterclockwise torques. Correcting the setup will lead to the accurate calculation of the tension in the rope.
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Homework Statement


A window washer is standing on a scaffold supported by a vertical rope at each end. The scaffold weighs 185 N and is 3.47 m long. What is the tension in the rope nearest the 747 N window washer when he stands 1 m from one end?


Homework Equations



sum of torques = zero
acceleration of gravity equals 9.8 m/s2

The Attempt at a Solution



I thought it was a simple problem but I get the answer wrong. My answer is 681.27 N. Is that right? If not how do i get the right answer??:eek:
 
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The first thing you need to do is to find an appropriate axis and put down all the torque effecting that point both clockwise and counterclockwise. Remember that the scaffold exerts its from the center of its mass.
 
I thought I did that. Is this the right set up?
0+185N(sin-90)(-1.735m) + 747N(sin-90)(-2.735)-3.47T=0
 
kitty9035 said:
I thought I did that. Is this the right set up?
0+185N(sin-90)(-1.735m) + 747N(sin-90)(-2.735)-3.47T=0
Here is your problem. Rewriting what you have written we have;

{\color{red}-}(185\times1.735){\color{red}-}(747\times2.735){\color{red}-}(3.47\times T)=0

This would mean that all the torques would tend to rotate the scaffold in the same direction, is the really what is happening?
 
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