What is the torque on the bolt due to the worker and the weight of the beam?

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SUMMARY

The torque on the bolt due to a 500 kg steel beam and a 70 kg construction worker is calculated by summing the individual torques produced by each weight. The torque from the beam, treated as concentrated at its midpoint, is 6350.4 N*m, while the torque from the worker standing at the end of the beam is 2469.6 N*m. The total torque about the bolt is therefore 8820 N*m. The initial miscalculation of the beam's mass as 360 kg was corrected to the accurate value of 500 kg.

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Homework Statement


A 3.60-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70kg construction worker stands at the far end of the beam

What is the magnitude of the torque about the bolt due to the worker and the weight of the beam?
(there was no diagram)

Homework Equations


torque = m*d

The Attempt at a Solution


I just summed the torques around the bolt and considered the beam as having all its mass at its center:
torque from beam: t = 360kg(9.8)(1.8m) = 6350.4N*m
torque from person: t = 70kg(9.8)(3.6) = 2469.6N*m
2469.6N*m + 6350.4N*m = 8820N*m

Is this correct and is my reasoning about beam as having its mass at midpoint correct? thanks for any help
 
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Yes but the beam is 500kg not 360kg
 

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