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sophbell
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Calculating Total Area Under a Trapezoidal Curve for Water Tank Fill Time
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- Thread starter sophbell
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- Tank Time Water Water tank
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SUMMARY
The discussion focuses on calculating the total area under a trapezoidal curve representing water tank fill time. The area consists of a right triangle (up to t = 2 hours) with legs measuring 2 and 200, and a rectangle with a width of 2 and height of 100. The area of the triangle is 200, and the area of the first rectangle is 200. To find the width of a second rectangle with a height of 300, the difference from 1000 must be calculated and used to determine the required width.
PREREQUISITES- Understanding of basic geometry concepts, specifically triangles and rectangles
- Familiarity with trapezoidal area calculations
- Knowledge of algebra for solving equations
- Ability to interpret graphical representations of mathematical concepts
- Study the properties of trapezoids and their area calculations
- Learn about the integration of curves for area under the curve calculations
- Explore algebraic methods for solving for unknown dimensions in geometric figures
- Investigate real-world applications of trapezoidal area calculations in engineering
Mathematicians, engineering students, and professionals involved in fluid dynamics or tank design who require precise area calculations for water fill times.
- #2
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The area represented under the curve is a triangle (up to t = 2 hours) plus a rectangle. How do you find the sum of that area?sophbell said:
-Dan
- #3
HOI
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Draw a horizontal line at "100" all the way across. Draw a vertical line at "2" all the way up and down. That divides the area into a right triangle with one leg of length 2 and the other of length 200, a rectangle with width 2 and height 100, and another rectangle with height 300 and unknown width. What is the area of the triangle and the first rectangle?
If that is less than 1000, subtract if from 1000. How wide must the second rectangle be so that its area is that difference?
If that is less than 1000, subtract if from 1000. How wide must the second rectangle be so that its area is that difference?
- #4
Prove It
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MHB
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topsquark said:
Surely it's a trapezium and a rectangle...
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