SUMMARY
The total distance covered by a subway train in 84 seconds can be calculated by breaking the motion into three segments: acceleration, constant speed, and deceleration. The train accelerates at 1.60 m/s² for 14.0 seconds, covering a distance of 158.4 meters during this phase. It then maintains a constant speed for 70.0 seconds, traveling an additional 280 meters. Finally, the train decelerates at 3.50 m/s² until it stops, covering 56 meters. The total distance covered is 494.4 meters.
PREREQUISITES
- Kinematic equations for uniformly accelerated motion
- Understanding of acceleration, constant speed, and deceleration
- Basic algebra for solving equations
- Knowledge of units of measurement (meters, seconds)
NEXT STEPS
- Study the kinematic equations: \(d = vt + \frac{1}{2}at^2\)
- Learn how to analyze motion in segments for complex problems
- Explore examples of constant acceleration and deceleration scenarios
- Practice problems involving distance, speed, and acceleration calculations
USEFUL FOR
Students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples of motion analysis.