Calculating Total Force on Diving Bell's Port

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To calculate the total force on the port of an evacuated spherical diving bell at a depth of 121 m, the total pressure must be determined by adding the seawater pressure to the atmospheric pressure. The seawater pressure can be calculated using the density of seawater (1025 kg/m³) and the depth. Some participants noted that atmospheric pressure could be neglected due to its relatively small contribution, but others argued that it should be included since the bell is evacuated, leading to a near vacuum inside. The force on the port is ultimately derived from the pressure difference across the port multiplied by its area. Accurate calculations require careful consideration of both pressures to ensure correct results.
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Homework Statement



An evacuated spherical diving bell containing a camera is in the ocean at a depth of 121 m. It has a flat, transparent, circular port with a diameter of 19.7 cm. Find the magnitude of the total force on the port (use ρseawater) = 1025 kg/m3).

Homework Equations



P(total)= ρgh+P(atm)
A=\piR^2


The Attempt at a Solution



I know that you need to find the total pressure on the bell. And then i think you have to subtract that total pressure from atmospheric pressure. this is what i have been doing and it is not working correctly. does anyone have any ideas?

Thanx!
 
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Force = pressure x area. You know the pressure of the water at that depth, since density is known. Rest is easy. Atm presssure may be neglected.
 
Just to amplify what Shooting star is saying, the reason you can neglect atmospheric pressure is not because it is terribly small. It's about ten percent of the seawater pressure, but because you should probably assume there is also atmospheric pressure inside of the bell, so it cancels. Just use the rhoseawater they gave you together with the area.
 
Last edited:
Total force on the port:

pressure/area from seawater on one side
pressure/area from 1atm on the other side
 
Hi Dick,

The problem specifically states that the sphere has been evacuted. So, inside is almost vacuum.

To be realistic then, P_atm should be added to the water pressure, since 1/10 of the water pressure is not really negligible.
 
Shooting star said:
Hi Dick,

The problem specifically states that the sphere has been evacuted. So, inside is almost vacuum.

To be realistic then, P_atm should be added to the water pressure, since 1/10 of the water pressure is not really negligible.

In that case, yes, it should. Sorry, I should read more carefully!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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