Calculating Total Rate of Conduction of Heat Through Clothing

[Priscilla]

Homework Statement

A mountain climber has a body surface of 1.80 m2 and wears fibrous clothing 1.00 X 10-2 m thick. He has a skin temperature of 33.1 ºC while the outer surface of his clothing is at 273.15 K. Calculate the total rate of conduction of heat through his clothing in Watts,
(a) taking the thermal conductivity of his dry clothing to be 0.0400 W m-1 K-1,
(b) assuming that that clothing is wet through and that the appropriate thermal conductivity is that of water (0.61 W m-1 K-1).

Homework Equations

P=kA (delta T/ delta x)

The Attempt at a Solution

a) P= (0.0400W/mK)(1.80m^2)[(33.1ºC - 0ºC)/ 1.00e-2 m) = 238.32W
b) P = (0.61W/mK)(1.80m^2)[(33.1ºC - 0ºC)/1.00e-2 m) = 3634.38W

 

[Borek]

Watch significant figures.