Calculating Transverse Acceleration in Waves and Tension

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SUMMARY

The discussion focuses on calculating transverse acceleration in waves on a wire under tension. Two specific scenarios are presented: one involving a 7.0 m wire with a frequency of 160 Hz and another with a 2.0 m wire at 330 Hz. The maximum transverse acceleration can be derived using the formula a = ω²A, where ω is the angular frequency and A is the amplitude. Participants seek clarification on applying partial differentiation to these calculations and determining the time for a wave crest to travel the wire's length.

PREREQUISITES
  • Understanding of wave mechanics, specifically transverse waves.
  • Familiarity with harmonic motion and its equations.
  • Knowledge of partial differentiation and its application in physics.
  • Basic grasp of tension in strings and its effect on wave propagation.
NEXT STEPS
  • Learn how to calculate angular frequency (ω) from frequency (f) in wave mechanics.
  • Study the derivation of transverse acceleration in harmonic motion.
  • Explore the relationship between wave speed, tension, and mass per unit length in strings.
  • Investigate the application of partial differentiation in physics problems involving wave motion.
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Physics students, educators, and anyone interested in wave dynamics and harmonic motion calculations will benefit from this discussion.

Soaring Crane
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1) A wire, 7.0 m long with a mass of 50 g, is under tension. A traverse wave is propagated on the wire, for which the frequency is 160 Hz, the wavelength is .60 m, and the amplitude is 2.1 mm. The maximum transverse acceleration, of a point on the wire, in SI units is closest to:

a. 1600-------b.1300--c.1900-----d.2100------e.2400

Exactly what is the transverse acceleration in theory/formula? I know that partial derivatives are involved, but I don't understand how to use partial differentiation. Any hints for this problem are appreciated.




2) A wire, 2.0 m long, with mass of 40 g, is under tension. A transverse wave is propagated on the wire, for which the frequency is 330 Hz, wavelength is 0.50 m, and amplitude is 2.9 mm. The time, for a crest of the wave to travel the wire's length, in ms, is closest to:

a. 15------b. 12-----c. 16----d. 11----e. 14


v = sqrt(F_T/(m/L))
m = 0.04 kg
L = 2.0 m

F_T = 9.8 m/s^2*0.04 kg

v = sqrt[F_T/(0.04 kg/2.0 m)] = 4.4272 m/s

f = 4.27 m/s/0.50 m = 8.54 1/s

T = 1/8.54 s^-1 = 0.1172 s*(1000 ms/s) = 117.2 s

Now I am lost. How do I find the time for the crest with the amplitude and frequency?

Thanks.
 
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Could anyone give me any hints for #1?

Thanks again.
 
Soaring Crane said:
Could anyone give me any hints for #1?

Thanks again.

The wave has a specified frequency, so you know the wave is harmonic. Each point on the string is moving perpendicular to the length of the string (transversely) in harmonic motion with the wave frequency and wave amplitude. Relate this to what you know about the motion of any harmonic oscillator.
 

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