MHB Calculating Travel Time for Light in an Optical Fiber

  • Thread starter Thread starter chrisliu1234
  • Start date Start date
  • Tags Tags
    Interference
chrisliu1234
Messages
2
Reaction score
0
Figure 35-57 shows an optical
fiber in which a central plastic
core of index of refraction n1 
1.58 is surrounded by a plastic
sheath of index of refraction n2 
1.53. Light can travel along different
paths within the central
core, leading to different travel times through the fiber.This causes an
initially short pulse of light to spread as it travels along the fiber,
resulting in information loss. Consider light that travels directly along
the central axis of the fiber and light that is repeatedly reflected at the
critical angle along the core–sheath interface, reflecting from side to
side as it travels down the central core. If the fiber length is 300 m,
what is the difference in the travel times along these two routes?

I know that I need to use t=L/v1=n1*L/c which becomes t=L/v1*cos(theta)=n1*L/(c*sqrt(1-(sin(theta)/n1)^2), but now I am stuck trying to figure the time for the question.
 
Mathematics news on Phys.org
chrisliu1234 said:
Figure 35-57 shows an optical
fiber in which a central plastic
core of index of refraction n1 
1.58 is surrounded by a plastic
sheath of index of refraction n2 
1.53. Light can travel along different
paths within the central
core, leading to different travel times through the fiber.This causes an
initially short pulse of light to spread as it travels along the fiber,
resulting in information loss. Consider light that travels directly along
the central axis of the fiber and light that is repeatedly reflected at the
critical angle along the core–sheath interface, reflecting from side to
side as it travels down the central core. If the fiber length is 300 m,
what is the difference in the travel times along these two routes?

I know that I need to use t=L/v1=n1*L/c which becomes t=L/v1*cos(theta)=n1*L/(c*sqrt(1-(sin(theta)/n1)^2), but now I am stuck trying to figure the time for the question.

Hi chrisliu1234! Welcome to MHB! (Smile)

Let's start with $t=\frac{n_1 L}{c}$ for the time to travel along the central axis.
Did you find the corresponding time?

As for the light traveling at critical angles, you're supposed to deduce a formula without theta.
Is that perhaps where your problem is? (Wondering)
 
I like Serena said:
Hi chrisliu1234! Welcome to MHB! (Smile)

Let's start with $t=\frac{n_1 L}{c}$ for the time to travel along the central axis.
Did you find the corresponding time?

As for the light traveling at critical angles, you're supposed to deduce a formula without theta.
Is that perhaps where your problem is? (Wondering)

So does change in time = t zigzag - t direct = n1^2*L/n2*c - n1*L/c?
 
chrisliu1234 said:
So does change in time = t zigzag - t direct = n1^2*L/n2*c - n1*L/c?

That looks right yes. (Nod)
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top