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## Homework Statement

d1 = 2.53 cm +/- .05 cm

d2 = 1.753 m +/- .001 m

0 = 23.5 degrees +/- .5 degrees

v1 = 1.55 m/s +/- .15 m/s

Using the measured quantities above, calculate the following. Express the uncertainty calculated value.

## Homework Equations

d3 = 4 ( d1 + d2)

## The Attempt at a Solution

d3 = 4 (2.53 cm +/- .05 cm) + (1.753 m +/- .001 m)

d3 = 10.12 +/- .2 cm + 7.012 m +/- .004 m

d3 = 10.32 cm + 7.016 m

I don't understand this problem so I would appreciate some help.