Calculating Undamped Natural Frequency of a Cantilever Beam

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SUMMARY

The discussion focuses on calculating the undamped natural frequency of a cantilever beam with specific parameters: a beam mass of 1.946 kg, a spring mass of 0.134 kg, and a motor block mass of 5.250 kg. The experimental undamped frequency was determined to be 2.74 Hz, equating to 0.437 rad/s. The user encountered difficulties calculating the moment of inertia (Io) using the formula Io = (mL^2)/12 + mL^2, resulting in an incorrect angular frequency (omega) of 7.0806 rad/s, which is significantly higher than the experimental value.

PREREQUISITES
  • Understanding of cantilever beam dynamics
  • Familiarity with moment of inertia calculations
  • Knowledge of oscillation frequency formulas
  • Basic experience with experimental data analysis
NEXT STEPS
  • Review the derivation of the moment of inertia for composite bodies
  • Learn about the relationship between frequency and moment of inertia in oscillatory systems
  • Explore the use of MATLAB or Python for simulating cantilever beam dynamics
  • Investigate the effects of added mass on the natural frequency of beams
USEFUL FOR

Mechanical engineers, students studying dynamics, and researchers involved in vibration analysis of structures will benefit from this discussion.

hwt
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Homework Statement


Hi.

I'm trying to work out the undamped natural frequency of a cantilever beam. The setup of the system is shown in the image below.

[URL]http://www.flickr.com/photos/56901717@N03/5249378659/[/URL]

Data:(all lengths measured from the hinge on the left of the beam)
Beam: m=1.946 kg, L=L1=815mm
Spring: m=0.134 kg, at length L3=815mm
Motor block: m=5.250 kg at L4=264mm

4 blocks of 50g mounted on motor at e=32mm from centre of rotation.
k=430 N/m

Homework Equations



The Attempt at a Solution



We began by finding the experimental undamped frequency from our plot from the oscilloscope.

F=1/T this gave a result of 2.74Hz = 0.437 rad/s

I then use the summation of moments about the hinge (say point O) to find an equation for natural frequency:

[URL]http://www.flickr.com/photos/56901717@N03/5250100964/in/photostream/[/URL]

My problem comes when calculating moment of inertia, Io:

I have tried using the equation:

Io = (mL^2)/12 + mL^2

However I don't think this is right as I get
omega = 7.0806 which is much much higher than my initial value.

Could someone please indicate where I am going wrong so I can have another attempt at this!

Thanks!
 
Last edited by a moderator:
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I couldn't use the in built formula editor too well so a knocked up the formula in word and saved it as an image. I think you may just have to right click on the image and copy the URL to see them!

Thanks for your help
 

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