Cantilever with end mass - Moment of inertia

Click For Summary

Discussion Overview

The discussion revolves around calculating the natural frequency of a cantilever beam with an end mass, focusing on the moment of inertia and its implications in the frequency equation. Participants explore the correct application of formulas and units related to moment of inertia, particularly in the context of beam theory and mass distribution.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant proposes a formula for natural frequency involving the moment of inertia and questions whether the moment of inertia should include both the cantilever and the end mass.
  • Another participant performs a dimensional analysis of the frequency formula, noting the need for clarification on the units used for moment of inertia and mass.
  • A participant points out a potential confusion between area moment of inertia and mass moment of inertia, suggesting that the terms used in the calculations may be mixed up.
  • There is a suggestion that the participant should consider whether the beam is massless or has a mass comparable to the end mass, which could affect the calculations.
  • One participant requests the formula for the moment of inertia of a rectangular beam and expresses confusion about the units being mm4.

Areas of Agreement / Disagreement

Participants express differing views on the correct interpretation and application of moment of inertia in the context of the problem. There is no consensus on the correct approach, as some participants identify potential errors while others seek clarification on specific aspects.

Contextual Notes

Participants highlight the importance of distinguishing between the area moment of inertia and the mass moment of inertia, indicating that the definitions and applications may not be fully aligned in the initial calculations.

Who May Find This Useful

This discussion may be useful for students and professionals dealing with structural mechanics, vibration analysis, and those interested in the dynamics of cantilever beams and their natural frequencies.

Dalmaril
Messages
3
Reaction score
0
Hello! I have a problem and if anyone could help that would be great.

Imagine that you have a cantilever beam of length L and has an end mass m. In order to calculate the natural frequency I use the equation:

f=(1/2*pi)*SQRT(3EI/mL^3).

a) The moment of inertia in the equation is the sum of both the cantilever and the mass, correct??
b) The moment of inertia of the mass is given through Steiner theorem: I = Ic + ma^2, where Ic = (bh^3)/12 (b and h are the mass' geometric characteristics) and a is the distance from the CM of the beam, correct??
c) The problem is that when I input these parameters to the frequency equation, I am not getting Hz at the end. Is (a) and (b) correct, cause that's where I think the problem is.

Thanks in advance!
 
Physics news on Phys.org
I didn't check the formula; I only did a dimensional analysis and I get s^(-1). I'm guessing you're using ips units? If so, what units are you using for I? For m?
 
E is in GPa , 1 Pa = 1 kg m^-1 s^-2
I is in m^4
m is in kg and L is in m.

But in the equation for the total I, there is the term of ma^2. Doesn't that have units kgm^2 or am i getting wrong somehow?
 
Only a quick answer. I'm rushing off and will visit later. But, you've criss-crossed moments terms. You can't use bh^3 (an area term) together with ma^2 (a mass term). See if you can straighten it out; if not, I'll give you a hand later.
 
Yes you are right, I saw that too :).. I need the area moment of inertia so the steiner theorem changes. I think that will do the trick. Thanks!
 
Dalmaril said:
Yes you are right, I saw that too :).. I need the area moment of inertia so the steiner theorem changes. I think that will do the trick. Thanks!

OK, that does indeed give you the right units. Now the big question: Have you used the correct I? Here's what you need to think about.
Is the beam considered massless?
Does the beam have significantly less mass than m?
Does the beam have a mass comparable to m?
Do you know the derivation of the formula you used?

HINT: Your formula looks like you're using an essentially massless beam and a point mass (what is the area of a point?).

I don't know what course you're in or whether you're interested in looking deeper, but here's a link you might look at (but only after you try it on your own).
http://www.vibrationdata.com/tutorials2/beam.pdf
 
So, did you figure out how to do this?
 
hello, I think you might mistake the moment of inertia [kg*m^2] for the second moment of area [m^4].
for the calculation of stiffness k is just m^4 for interest.
 
i need the formula for finding moment of inertia of rectangular beam. i have failed to know why the units are mm^4
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 14 ·
Replies
14
Views
10K
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
9
Views
8K