Calculating Velocity for a Banked Curve: What Factors Affect the Best Speed?

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SUMMARY

The discussion focuses on calculating the best velocity for a banked curve with a radius of 105 feet, a length of 30 feet, and a height of 4 feet. The key formula mentioned is tan(theta) = v^2 / (rg), leading to v = sqrt(rg tan(theta)). The participants highlight the importance of understanding the relationship between the curve's geometry and the angle theta, which is crucial for determining the optimal speed. Clarification on how the length and height relate to the curve's cross-section is also sought.

PREREQUISITES
  • Understanding of basic physics concepts such as centripetal acceleration and forces.
  • Familiarity with trigonometric functions, particularly tangent.
  • Knowledge of kinematic equations related to motion on curved paths.
  • Basic geometry related to curves and angles.
NEXT STEPS
  • Research the derivation of the formula v = sqrt(rg tan(theta)) in the context of banked curves.
  • Study the effects of different angles on the normal force and resultant forces in banked turns.
  • Explore the relationship between curve geometry and vehicle dynamics in physics.
  • Investigate practical applications of banked curves in road design and safety considerations.
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Physics students, civil engineers, and automotive engineers interested in the dynamics of vehicles on banked curves and the calculations involved in optimizing speed for safety and performance.

Visual1Up
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Can someone start me in the right direction?

Radius = 105ft
length = 30 ft
height = 4ft
theta = ?
best velocity = ?

I am guessing I use ... tan(theta) = v^2/rg ... v = sqrt(rg tan(theta))

But the empty theta confuses me, and I am not sure how the length even fits in, thanks!,

-Mike
 
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I would guess that the length and height are from the cross section of the road. If this is true, then you remember that for the best velocity, the normal force is the resultant of the weight and cent. acceleration force.
 
I am not sure I follow exactly, could you explain some more? Thanks!
 

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