Calculating Velocity in Circular Motion

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mccarthyp64
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1. All in the picture



2.v2=u2+2as



3. I have no idea where to start, I went through all the equations but i don't have time or velocity to sub in :(

It also has circular motion which may or may not introduce pi. I didn't think this would be relevant but anyway.
 

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mccarthyp64 said:
1. All in the picture



2.v2=u2+2as



3. I have no idea where to start, I went through all the equations but i don't have time or velocity to sub in :(

It also has circular motion which may or may not introduce pi. I didn't think this would be relevant but anyway.

The question concerns energy and energy conservation. What forms of energy can you identify in the scenario?
 
There is kinetic and potential gravitational energy
so Ek=1/2mv2 but that needs velocity so:
Ep=mgh but that only gives horizontal velocity whereas, I need all velocity.
 
mccarthyp64 said:
There is kinetic and potential gravitational energy
so Ek=1/2mv2 but that needs velocity so:
Ep=mgh but that only gives horizontal velocity whereas, I need all velocity.

Why do you need velocity? What will velocity tell you?

Why do you suppose that the height of the object only reaches 0.14 m after it breaks the pencil rather than returning to its starting height of 0.30 m? What has changed?
 
for q 25 velocity is the answer
and in 26 I need the work done
 
mccarthyp64 said:
for q 25 velocity is the answer
and in 26 I need the work done

Both questions involve changes in energy. Consider the energy changes taking place.
 
Ep=mgh=Ek=1/2mv2
1.176=0.4*9.8*0.3=1.176=0.5(0.4)(v)2
(1.176/0.5)/0.4=v2=5.88
√(5.88)=2.42=ANS!
YAY thanks gneill :)