Calculating Velocity in Circular Motion

AI Thread Summary
The discussion focuses on calculating velocity in circular motion using energy conservation principles. Key equations mentioned include v² = u² + 2as and the relationships between kinetic energy (Ek) and potential energy (Ep). Participants express confusion about how to apply these equations, particularly in determining total velocity when height changes occur. The conversation highlights the importance of understanding energy transformations, as well as the specific values needed for calculations. Ultimately, the correct velocity is derived as approximately 2.42 m/s through the application of these principles.
mccarthyp64
Messages
5
Reaction score
0
1. All in the picture



2.v2=u2+2as



3. I have no idea where to start, I went through all the equations but i don't have time or velocity to sub in :(

It also has circular motion which may or may not introduce pi. I didn't think this would be relevant but anyway.
 

Attachments

  • physics question.png
    physics question.png
    33.4 KB · Views: 535
Physics news on Phys.org
mccarthyp64 said:
1. All in the picture



2.v2=u2+2as



3. I have no idea where to start, I went through all the equations but i don't have time or velocity to sub in :(

It also has circular motion which may or may not introduce pi. I didn't think this would be relevant but anyway.

The question concerns energy and energy conservation. What forms of energy can you identify in the scenario?
 
There is kinetic and potential gravitational energy
so Ek=1/2mv2 but that needs velocity so:
Ep=mgh but that only gives horizontal velocity whereas, I need all velocity.
 
mccarthyp64 said:
There is kinetic and potential gravitational energy
so Ek=1/2mv2 but that needs velocity so:
Ep=mgh but that only gives horizontal velocity whereas, I need all velocity.

Why do you need velocity? What will velocity tell you?

Why do you suppose that the height of the object only reaches 0.14 m after it breaks the pencil rather than returning to its starting height of 0.30 m? What has changed?
 
for q 25 velocity is the answer
and in 26 I need the work done
 
mccarthyp64 said:
for q 25 velocity is the answer
and in 26 I need the work done

Both questions involve changes in energy. Consider the energy changes taking place.
 
Ep=mgh=Ek=1/2mv2
1.176=0.4*9.8*0.3=1.176=0.5(0.4)(v)2
(1.176/0.5)/0.4=v2=5.88
√(5.88)=2.42=ANS!
YAY thanks gneill :)
 

Similar threads

Back
Top