Calculating Velocity of a Man Jumping from 90m Building | Physics Question

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SUMMARY

The velocity of a man jumping from a height of 90 meters, under the influence of gravity at 9.8 m/s², can be calculated using the kinematic equation vf² = vi² + 2ax. By substituting the initial velocity (vi) as 0, acceleration (a) as 9.8 m/s², and distance (x) as 90 m, the final velocity (vf) is determined to be 42 m/s upon impact with the ground. The weight of the individual does not affect the calculation of velocity in free fall.

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IF a man jumps off a building that is 90 m high, and gravity is 9.8 m/s, and he weighs 80 kg, then what will his velocity be just as he hits the ground?
 
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just use the equation

vf^2=vi^2 +2ax
vf^2=0+2(9.8)(90)
vf^2=1764
v=42 m/s

weight is irrelevant
 

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