Calculating Velocity Using Length Contraction Formula in Relativity Theory

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Homework Help Overview

The problem involves calculating the velocity of a spaceship using the length contraction formula from relativity theory. The original poster measures the spaceship's length as 300 m, while an astronaut on the ship measures it as 445 m.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the length contraction formula but encounters issues with negative results. Participants question the correctness of the substituted values for proper length and the roles of the observers.

Discussion Status

Participants are actively discussing the proper application of the length contraction formula, clarifying the definitions of proper length and the lengths measured by different observers. There is a recognition of the need to switch the values assigned to the lengths based on the observers' frames of reference.

Contextual Notes

There is an ongoing discussion about the definitions of proper length and the lengths observed by different observers, which may lead to confusion in the application of the formula. The original poster's calculations are constrained by these definitions and their understanding of the scenario.

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Homework Statement


A spaceship moves past you at speed v. You measure the ship to be 300 m long, whereas an astronaut on the ship measures a length of 445 m. Find v.

The Attempt at a Solution


I tried to substitute my numbers into L1=Lsqrt(1/(v^2/c^2)) and keep getting a negative wrong answer!
445=300sqrt(1-(v^2/3E+8^2)) ... what am i doing wrong?
 
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In your formula L (on the right hand side) is the proper length. Are you sure you have substituted the proper length correctly?
 
Pi-Bond said:
In your formula L (on the right hand side) is the proper length. Are you sure you have substituted the proper length correctly?

Well L1 is supposed to be the length observed by an observer in relative motion with respect to the object, which would be 445?
 
But the astronaut is at rest relative to the spaceship. Who is the one measuring the moving spaceship?
 
Pi-Bond said:
But the astronaut is at rest relative to the spaceship. Who is the one measuring the moving spaceship?
I guess that means i am, so i switch 300 and 445?
 
Yes. The right hand side of your equation deals with proper length, or the length measured by an observer in the rest frame of the object. (Astronaut in this case) The left side deals with what an observer in relative motion will measure as the length. (you in this case)
 
Pi-Bond said:
Yes. The right hand side of your equation deals with proper length, or the length measured by an observer in the rest frame of the object. (Astronaut in this case) The left side deals with what an observer in relative motion will measure as the length. (you in this case)

aha i see, thank you so much!
 

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