Calculating Vertical Distance of Electron in 2D Motion

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Homework Help Overview

The problem involves calculating the vertical distance an electron travels while moving horizontally towards a screen after being ejected from a gun. The context is within the subject area of kinematics, specifically dealing with projectile motion under the influence of gravity.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to consider both horizontal (Vx) and vertical (Vy) components of motion. There are questions regarding the application of standard equations of motion and how to relate the time of flight to vertical displacement.

Discussion Status

Some participants have offered guidance on using horizontal motion to determine time, which can then be applied to vertical motion. However, there remains a lack of explicit consensus on the exact steps to take, as some participants express confusion about the components involved.

Contextual Notes

Participants note the requirement to show their own attempts and reasoning before receiving further assistance, indicating a focus on individual effort in problem-solving.

Soulax
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An electron is ejected horizontally at a speed of 1.5*10^6 m/s from the electrong gun of a computer monitor.
if the viewing screen is 0.35m from the end of the gun, how far will the electron travel in the vertical direction before hitting the screen?

so what I don't get is if they want me to calculate the distance before it hits the screen and if yea how do I do it? I know Ill have to take in account Vx and Vy but I am not sure of the data they give me...

Thanks allot!
 
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Hi Soulax! :wink:

An electron is just like any other projectile under gravity …

use the standard constant acceleration equations. :smile:
 
I know that.. its not the problem I don't know what to do with x and y components
 
Use x to find the time, t, then use that time in y …

what do you get? :wink:
 
hmm sorry didnt get it :P can you show me an example please?
 
(just got up :zzz: …)

Sorry, on this forum you have to do it yourself. :wink:

Show us what you tried, and where you're stuck, and then we'll know how to help! :smile:
 
its ok I got it my broblem was that I didnt understand the right situation :)

thank you verymuch anyway :)
 

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