Calculating Vertical Velocity and Force: Jumping Physics Problems"

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Homework Help Overview

The problem involves calculating the vertical velocity and force exerted by a boy during a jump. The boy has a mass of 82 kg and achieves a vertical leap of 1.2 m. Participants are tasked with finding the initial vertical velocity required to reach this height and the force exerted during a 30 cm lift after crouching.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using kinematic equations to determine the initial velocity, with one participant applying the equation v2^2 = v1^2 + 2a(d). There is also a focus on calculating the force during the lift, with questions about the correct interpretation of forces involved.

Discussion Status

Some participants have shared their calculations for the initial velocity and the force exerted during the jump. There is an ongoing clarification regarding the distinction between net force and the force exerted by the ground, indicating a productive exploration of the concepts involved.

Contextual Notes

Participants are discussing the implications of using different values for acceleration and the need to separate forces acting on the boy during the jump. There is uncertainty about the correctness of the calculations presented.

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Homework Statement




A boy has a mass of 82kg, and a vertical leap of 1.2m ,
Find the vertical velocity he leaves the ground to reach a max of 1.2m
Find the force he pushes during the 30 cm lift if he squats 30 cm before jumping

Homework Equations





The Attempt at a Solution



I used v2^2=v1^2+2a(d) to find what the v1 was, assuming v2 was 0 at the max.
 
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Yes, that's right, what did you get for the initial velocity?
 
I got sqrt of 23.52 for the initial velocity when he is standing up straight

As for the force he applied when lifting the 30 cm after crouching I got,
3214.4N

for the 3214.4N , I found the acceleration he had during the 30 cm or .3m then multiplied it by his weight. I had v1 as 0 for this part.

Not sure if its 100% right tho
 
I used -9.8 m/s^2 (up) for acceleration for the first part of the question to find sqrt 23.52 as my initial velocity
 
kooh said:
I got sqrt of 23.52 for the initial velocity when he is standing up straight
good!
As for the force he applied when lifting the 30 cm after crouching I got,
3214.4N

for the 3214.4N , I found the acceleration he had during the 30 cm or .3m then multiplied it by his weight. I had v1 as 0 for this part.

Not sure if its 100% right tho
you multiplied it by his mass, not his weight, and what you ended up with was the net force acting on him during the 30 cm 'squat' motion. But the net force includes both the force of the ground pushing up on him and his weight acting down on him. You need to separate out the 2 to find the pushing force of the ground on him.
 

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