Calculating Viscosity of Golden Syrup through Terminal Velocity Experiment

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SUMMARY

The discussion focuses on calculating the viscosity of golden syrup using a terminal velocity experiment with steel ball bearings. The participant intends to plot the square of the radius (r²) against the terminal velocity (Vterm) to derive the viscosity (η) from the gradient of the resulting graph. The correct formulation is established as Vterm = (2g(ps - pg) / 9η) * r², leading to the conclusion that η can be calculated using the equation η = 2g(ps - pg) / (9 * gradient).

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Homework Statement



I'm going to be doing an experiment to determine the viscosity of golden syrup by dropping different size steel ball bearings into a jar of golden syrup and recording how long it takes for them to travel a certain distance when there at terminal velocity.

so from the formula I'm trying to calculate eta, but I must do this by plotting a graph and then calculating eta from the gradient

Homework Equations



258ovae.png


The Attempt at a Solution



I think I'm going to have to plot radius^2 on one axis and Vterm on the other axis but I'm not sure which goes which. and then I'm going to make the equation in the same format of y=mx but I'm not sure again how
 
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is this correct vterm on y-axis and r^2 on x-axis and then the equation of the line would equal = (vterm=2g(ps-pg))/9eta *r2 +0 and then from this

eta = 2g(ps-pg) / 9*gradient ?
 

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