Calculating Volume of Acetone for Solution with Methylene Chloride

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SUMMARY

The discussion centers on calculating the volume of acetone required to create a solution with 20.3 g of methylene chloride (CH2Cl2) per 100 g of solution, given 1790 g of the solute. The molar masses are provided: methylene chloride at 84.93 g/mol and acetone ((CH3)2CO) at 58.05 g/mol. The density values are also specified, with methylene chloride at 1.327 g/mL and acetone at 0.7899 g/mL. The solution requires understanding the mass percent equation and converting mass to volume using density.

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Homework Statement



What volume (L) of the solvent acetone should be added to 1790 g of the solute methylene chloride to make a solution that is 20.3 g methylene chloride per 100. g solution?


Molar Mass (g/mol)
CH2Cl2 84.93
(CH3)2CO 58.05
Density (g/mL):
CH2Cl2 1.327
(CH3)2CO 0.7899
Name/Formula:
methylene chloride
CH2Cl2
acetone
(CH3)2CO

Homework Equations



percent by mass = mass of solute/ mass of solution x 100

The Attempt at a Solution


Im taking organic chem right now and this is a question for one of my chem lab homeworks so I am a little rusty with these kinds of problems...but this is where I am at/stuck

Looking for (L) of (CH3)2CO Given: 1790g CH2Cl2 and the mass percent fraction is:
20.3g CH2Cl2/100g soln.

I know that you have to use the densities to convert from g-->L but I just don't know how to get to that point..
 
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That means that you have a solution which is made of the ratio 203 parts mass methylene chloride to 797 parts mass acetone. This is based on 1000 parts mass of solution. Now, scale this up to 1790 parts mass of solution.
 
ah! yes, thank you...
 

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