Calculating Water Friction for Dropped Objects

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Homework Help Overview

The discussion revolves around calculating the effects of water friction on an object dropped into water, specifically addressing the theoretical versus actual acceleration due to drag forces in a fluid medium.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the concept of drag in fluids, questioning how to incorporate water friction into their calculations. They discuss the use of drag equations and the implications of varying velocities on drag force.

Discussion Status

Participants are actively engaging with the topic, sharing resources and equations related to drag. There is a focus on understanding the relationship between drag, velocity, and acceleration, with some guidance provided on using specific drag equations.

Contextual Notes

There is an emphasis on the conditions under which the drag equations apply, such as maintaining small speeds for laminar flow, and considerations regarding whether to treat acceleration as variable or constant.

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In my current scenario, I have something that was dropped from above water. I have found the theoretical acceleration of the object when it is under water (it had entered the water with some initial downward velocity) already from boyancy - weight = ma. However, in reality that acceleration is going to be smaller because of water friction. How do I take into account water friction? I know it can't be u*N which is what friction is on land.

Thanks
 
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Try http://www.hypertextbook.com/physics/matter/drag/" (it has a reasonable explanation). Just remember the problem with drag in a fluid is not as easy as you might think.
 
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Thanks for the link. How can I use the value of drag though? What equation can I use to then find out the increase in time drag creates over an ideal fluid or the lessening in velocity?
 
Well for all purposes you can use [itex]F_{drag} = C_{drag} \frac{\rho v^{2}}{2} A[/itex] as long as you keep small speeds, therefore there will be a small Reynolds number (laminar flow). A is surface area, and [itex]C_{drag} = \frac{24}{N_{reynolds}}[/itex] in this case.
 
Last edited:
Thanks again. I'm assume that the best way to find the F drag with a changing velocity is to take the average and use that as v, right?
 
Well it depends on your approach. Do you want a variable or constant acceleration?, if its the former then you'll need to solve the differential equation, for the later you could use the average velocity.
 

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