Calculating Wavelength from Double-Slit Interference Pattern

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The problem involves calculating the wavelength of light using a double-slit interference pattern with slits spaced 0.21 mm apart and a screen 60 cm away. The distance between the first and fifth minimum is given as 6.2 mm. The initial calculation for delta y was incorrectly derived, leading to a wavelength of 434 nm, which was identified as incorrect. Clarification was sought on whether the distance should be halved if 6.2 mm represented the distance between the first and second minima. Accurate interpretation of the distance between minima is crucial for correct wavelength calculation.
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Homework Statement



A double-slit interference pattern is created by two narrow slits spaced 0.21mm apart. The distance between the first and the fifth minimum on a screen 60cm behind the slits is 6.2mm. What is the wavelength of the light used in this experiment?


Homework Equations



gamma = d/L * Delta y

The Attempt at a Solution



delta y = 6.2mm/5 = 1.24*10 ^-3m
gamma = d/L delta y
= (2.1*10^-4m)/0.6m * 1.24*10^-3
= 434nm
but this is incorrect. Where did I go wrong?
 
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If the 6.2 mm was the distance between the first and second minima, would you say the distance between the minima is Δy = 6.2 mm/2?
 
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