Calculating weight needed for micromole of solution

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SUMMARY

The discussion focuses on calculating the weight of neutral red required to create a 40.0 µM solution in 1.00 ml. The molecular weight of neutral red is established as 289 g/mol. To find the necessary weight in micrograms, participants emphasize the conversion from grams to micrograms, noting that 1 gram equals 1,000,000 micrograms. The solution involves using the formula for molarity and converting the final answer appropriately.

PREREQUISITES
  • Understanding of molarity and its calculation
  • Basic knowledge of molecular weight and its application
  • Conversion between grams and micrograms
  • Familiarity with unit conversions in chemistry
NEXT STEPS
  • Learn about calculating molarity for different concentrations
  • Study the conversion techniques between different metric units
  • Explore the concept of molecular weight and its significance in solution preparation
  • Review examples of preparing solutions in laboratory settings
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Chemistry students, laboratory technicians, and anyone involved in solution preparation and concentration calculations.

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Homework Statement


Here is the question:
What weight of neutral red (molecular weight 289) must be dissolved in 1.00 ml to give a =40.0 µM (µmol l-1) solution? Give your answer in MICROGRAMS (µg).

Homework Equations


Not sure the only one I'm aware of is mole concentration (mol dm^-3) = moles/volume but I can't seem to find the answer using this.

The Attempt at a Solution


i. I understand that moles dm^-3 = moles/volume but this is in Micrograms so I am a bit confused.[/B]
 
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Start calculating how many grams you need, conversion from g to μg is rather trivial.
 

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