SUMMARY
The work done on a 15.0N object moved horizontally 3.00m using a horizontal force of 60.0N is calculated using the formula for work, W = F × d, where F is the force applied in the direction of motion. In this case, the relevant force is 60.0N, as the weight of the object (15.0N) acts perpendicular to the direction of motion and does not contribute to the work done. Therefore, the total work done is W = 60.0N × 3.00m = 180.0 Joules.
PREREQUISITES
- Understanding of Newton's Second Law of Motion
- Familiarity with the concept of work in physics
- Knowledge of force vectors and their components
- Basic arithmetic for calculating work done
NEXT STEPS
- Study the principles of Newton's laws of motion
- Learn about the concept of work and energy in physics
- Explore vector components and their applications in physics
- Practice calculating work done with different forces and distances
USEFUL FOR
Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of work and force in physical systems.