Calculating Work and Power: Force of 5N on a 15kg Body at Rest

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SUMMARY

The discussion focuses on calculating work and power for a 15kg body subjected to a constant force of 5N. The work done by the force is computed using the equation W = Fd, where 'd' is the distance traveled. To find the distance as a function of time, the acceleration must be integrated, allowing for the calculation of work done in the first three seconds. Instantaneous power at the end of the third second can be determined using the formula P = Fv, where 'v' is the velocity of the body at that time.

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Homework Statement


A force of 5N acts on a 15kg body initially at rest. Compute the work done by the force in: first, second, and third seconds, the instantaneous power to the force at the end of the third sec.


Homework Equations


W=fd
P=(dW)/(dt)


The Attempt at a Solution


I'm not quite sure how to work this out with just the equation W=fd, but I know work is also mass X integral of acceleration vs. position. I guess my biggest problem is not knowing where to put time...
Thanks in advance
 
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If you had an expression for the distance, s, traveled as a function of time, then you could find the work by calculate how far the body moves from t=0 to t=1, and then again from t=1 to t=2, and once more from t=2 to t=3, and the use W = Fs (using 's' instead of 'd' in order not to confuse distance with differentiation).

For the power you should notice that P = dW/dt = d(Fs)/dt = F ds/dt = F v, under the assumption that F is constant. So you can also find power if you know the speed of the body at the time in question.
 

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