Calculating work done by a force?

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To calculate the work done by an applied force on an object moving from an elevation of 5 m to 20 m with changing velocities, the equation Work = Change in KE + Change in PE is used. However, the mass of the object is not provided, making it impossible to determine a numerical value for the work done. The discussion concludes that the question may be asking for a formula rather than a specific answer, with mass as a variable. It is also noted that the units of mass should be specified to ensure the work is expressed in kilojoules. The overall implication is that the problem lacks sufficient information for a complete solution.
chrismeng
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Homework Statement


An object initially at an elevation of 5 m relative to the Earth's surface with a velocity of 50 m/s is acted on by an applied force R and moves along a path. Its final elevation is 20 m and its velocity is 100 m/s. The acceleration of gravity is 9.81 m/s^2. Determine the work done on the object by the applied force, in kJ.

Homework Equations


Work of all non-gravity forces = Change in KE + Change in PE

The Attempt at a Solution


I can get the work done by R in terms of the mass using the equation
Work of all non-gravity forces = Change in KE + Change in PE
but the problem doesn't tell us the mass and I don't know what other equation to use to set up a system of equations to eliminate the mass.
 
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Welcome to PF!

You are right. Without the mass, you cannot find a numerical value for the work done by the applied force.
 
TSny said:
Welcome to PF!

You are right. Without the mass, you cannot find a numerical value for the work done by the applied force.
I thought so! thanks for the help
 
I get the impression that the conclusion is that the question is invalid. Not necessarily so however. Since the result is dependent on the unknown mass, it likely should be presumed that the question is simply asking for a formula as an answer, with the mass as a parameter in it. One would also have to specify the units of the mass in such an answer since the question is so specific in asking that the work deduced is explicitly in kj.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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