# Calculating Work Done by a Variable Applied Force

• MissPenguins
In summary, the applied force F varies with position according to F = k1xn - k2, where n = 3, k1 = 8.3 N/m3, and k2 = 87 N. The work done by this force on an object that moves from xi = 6.47 m to xf = 14.9 m is 97.904 kJ. The calculation formula is W = k1 x^4/4 - k2 x. Make sure to use enough digits during the calculations to avoid errors.
MissPenguins

## Homework Statement

An applied force varies with position according to F = k1xn - k2, where n = 3, k1 = 8.3 N/m3, and k2 = 87 N. How much work is done by this force on an object that moves from xi = 6.47 m to xf = 14.9 m? Answer in units of kJ.

## Homework Equations

W = k1 x4/4 ]from the integral of x1 to x2
- k2x]from x1to x2

## The Attempt at a Solution

I plugged in everything, and I got 96.778 at first, then I thought I should use x33/3, then I got 6.543478 kJ.
SOLVED

Last edited:
Agree with W = k1 x^4/4 - k2x from x1 to x2.

Delphi51 said:
Agree with W = k1 x^4/4 - k2x from x1 to x2.

I still didn't get that answer. :(

It is really W = k1 x^4/4 - k2 x , and I got 97904, similar to your result. Use enough digits during the calculations. ehild

ehild said:
It is really W = k1 x^4/4 - k2 x , and I got 97904, similar to your result. Use enough digits during the calculations.

ehild

I found my mistake, thank you very much.

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