Calculating Work Done by a Varying Force: Positive or Negative?

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SUMMARY

The discussion centers on calculating the work done by a varying force defined by the equation F=(7Nxm^2)x^-2 for an object with a mass of 2 kg, moving from x=2 to x=3. The work done is determined by integrating the force over the specified distance. The integral of the force function will yield the total work, which can be classified as positive or negative based on the direction of the force relative to the displacement.

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  • Understanding of Newton's laws of motion
  • Knowledge of calculus, specifically integration
  • Familiarity with the concept of work in physics
  • Basic grasp of force and mass relationships
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williams31
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An object of mass 2 kg is repelled from the origin by a force in the +x-direction whose magnitude varies with x according to F=(7Nxm^2)x^-2. How much work is done by this force when the object moves from x=2 to x=3? (Be sure to say whether this work is positive or negative.)


I have no idea how to start this problem off. Anybody want to help me out?
 
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What is the equation that defines how much work is done, in terms of the force and distance through which the force acts? Work is the integral of what quantities?
 
You really should look through the link I gave you on the other thread.
 

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