Calculating Work Done by Gravity & Air Resistance on Raindrop

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Homework Help Overview

The problem involves calculating the work done by gravity and air resistance on a raindrop falling at constant speed. The raindrop is modeled as a particle with a specified mass and falls a vertical distance of 100 meters.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the raindrop, including gravity and air resistance, and question the implications of the net force being zero at constant speed. There are inquiries about the constancy of forces and how to apply them in the work equation.

Discussion Status

Participants are exploring the relationship between the forces acting on the raindrop and the work done by each force. Some guidance has been provided regarding the interpretation of net force and its implications for calculating air resistance, though no consensus has been reached on the specific calculations.

Contextual Notes

There is a mention of potential confusion regarding the values of forces and the conditions under which they are considered constant. Participants are encouraged to reflect on the assumptions made in the problem setup.

AryRezvani
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Homework Statement



A raindrop of mass 3.35x10-5 falls vertically at constant speed under the influence of gravity and air resistance. Model the drop as a particle. As it falls 100m, what is the work done on the raindrop. (a) by the gravitational force and (b) the air resistance.

Homework Equations



FΔrCosθ=W
Fg=mg


The Attempt at a Solution



Fg=mg=3.34x10-4

Force of gravity is acting downward, and air resistance is acting upwards so the net force is taken into account when using FΔrCosθ, right?

Lost after this step.

Why is the force constant? Just wondering?
 
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weight is a constant force. Air resistance is assumed to be constant at this level as well.
 


The drop is falling at constant speed. So the net force is zero.
 


Force of gravity = 9.8
Displacement = 100
Cos (90) = 1

But if the net force is zero, what do we plug into F for the equation?
 


The problem is asking you to find
a.) the work done by gravity and
b) the work done by the air resistance.
If the net force is 0 , which you should first ask yourself whether or why this is true, that would be key to finding the air resistance force, and the work done by it.
 


AryRezvani said:
Force of gravity = 9.8
Displacement = 100
Cos (90) = 1

But if the net force is zero, what do we plug into F for the equation?

Force of gravity is not 9.8. Check your values.
The questions tells you what force to plug into equation, for each part (a - force of gravity, b - force of air resistance).
The condition net force= 0 allows you to calculate the force of air resistance.
 

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