Calculating Work Done on a Slope: Friction and KE

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SUMMARY

The discussion centers on calculating work done on a slope involving friction and kinetic energy (KE). It establishes that when a box is pushed up a slope at constant speed, the work done by friction cannot be assumed to be zero, as friction depends on the weight of the box and the coefficient of friction. The formula for frictional force is given as f = Nµ = mgµ, indicating that work done by friction is the product of this force and the distance moved along the slope.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of work and energy in physics
  • Knowledge of frictional forces and coefficients of friction
  • Basic grasp of gravitational potential energy (U) and kinetic energy (KE)
NEXT STEPS
  • Study the relationship between frictional force and normal force in detail
  • Explore the concept of conservative vs. non-conservative forces in physics
  • Learn about the work-energy theorem and its applications
  • Investigate different types of friction and their effects on motion
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the dynamics of forces on inclined planes.

disruptors
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Hey ppl,

If you have a man pushing a box up a slope with a horizontal force at constant speed from distance a to b, can one assume the Work done by friction to be zero all the time since velocity is constant? or can one assume W(neoconservative)=change in U(gravitational PE) only, with change in KE=0...

Thanks
 
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disruptors said:
can one assume W(neoconservative)=change in U(gravitational PE) only, with change in KE=0...

Yes, but only if the man is a neoconservative. :-p
 
hahaha :smile:

disruptors said:
Hey ppl,

If you have a man pushing a box up a slope with a horizontal force at constant speed from distance a to b, can one assume the Work done by friction to be zero all the time since velocity is constant?

Well that would be true if the frictionnal force depended on the accelaration of the thing sliding on the surface. But it's usually not the case, and we can assume that the frictionnal force depends only on the weight of the box and on the coeficient of friction of the surface, such that f = Nµ = mgµ. So the work done by the fricton would have to be component of friction parallel to the surface times the distance b-a.
 

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