Calculating Work Done on an Object with a Constant Force

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The discussion focuses on calculating the work done on a 2 kg object by a constant force of 10 N acting at an angle of 150 degrees. The correct formula for work is W = \vec{F} \cdot \vec{\Delta r}, where \vec{F} is the force vector and \vec{\Delta r} is the displacement vector. The user initially miscalculated the displacement using the Pythagorean theorem, resulting in an incorrect value of -4.47. The correct approach involves calculating the dot product of the force vector and the displacement vector, which includes resolving the force into its components.

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a constant force of magnitude 10 N makes an angle of 150. (measured counterclockwise) with the direction of increasing x as the force ascts on the 2 kg object. how much work is done on the object by the force as the object moves from the origin to the point with position vector. (2m)i - (4m)j?

what did till now is w = f x d and force was equal to 10Cos 150 x (-4.47)
i used the pathoagorious theomrem and got the value -4.47. 2^2 + 4^2 and then found the root for that answer. but stil my answer is wrong. Could someone please explain me what i am doing wrong. Thanks a lot for the help.
 
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problem said:
a constant force of magnitude 10 N makes an angle of 150. (measured counterclockwise) with the direction of increasing x as the force ascts on the 2 kg object. how much work is done on the object by the force as the object moves from the origin to the point with position vector. (2m)i - (4m)j?

what did till now is w = f x d and force was equal to 10Cos 150 x (-4.47)
i used the pathoagorious theomrem and got the value -4.47. 2^2 + 4^2 and then found the root for that answer. but stil my answer is wrong. Could someone please explain me what i am doing wrong. Thanks a lot for the help.

[tex]W = \vec{F}\cdot \vec{\Delta r} = (10 \cos(150) \vec{i}+10 \sin(150) \vec{j})\cdot(2\vec{i}-4\vec{j})[/tex].
 
another quick question. There is a ramp at an angle now a box is being pushed up with certain force up a certain distance. The mass of the block is given. How can i figure out what the total work done is?
 

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