Calculating Work Output from Thermal Efficiency of Car Engine

[WhyPrime89]

Homework Statement

The power output of a car engine running at 1900 is 600 kilowatts per hour.
How much work is done per cycle if the engine's thermal efficiency is 30.0 percent

Homework Equations

thermal efficiency=w(out)/Q(hot)

The Attempt at a Solution

It wants the answer in KJ/s so i converted the kilowatts to KJ/sec then divided by rev/s then multiplied by .3. What am i doing wrong? Any help would be appreciated.

 

[Carid]

Looks like you should be multiplying by 10/3.
The 600 kw/hr seems to be the power output after 70% of the initial energy has been lost.