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I am having some trouble understanding why friction is not accounted for when calculating work done, as in the following two problems.

If an object is experiencing friction, wouldn't there need to be more work done to continue moving the object?

Thank you!

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1. A father is pulling his two girls in their toboggan with a force of 500 N for a distance of 22 m. Calculate the work that would be done by the father in each of the following cases.

a) The snow provides no friction.

b) One daughter drags her hand in the snow, producing a firctional force of 500 N.

My Work:

a) Work = Force x Distance

= 500 N x 22 m

= 1.1E4 J

b) Since there is 500 N of frictional force:

Work = 1000 N x 22 m

= 2.2E4 J <-- According to textbook, this answer is wrong.

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# Homework Help: Calculating Work - With Friction

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